解决内存allocate函数有可能访问未知内存的问题
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@ -6,14 +6,5 @@ edition = "2021"
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# 此Cargo.toml仅用于rust-analyzer识别rust部分的代码
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# 不应使用cargo编译
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[build]
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type = "staticlib"
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rustflags = [
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"-C", "embed-bitcode=no",
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"-C", "code-model=large",
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"-C", "relocation-model=static",
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"-L", "crate=${PWD}/../rustlib/${ARCH}/src/"
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]
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[target.'cfg(target_arch = "x86_64")']
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target = "x86_64-unknown-none"
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@ -139,9 +139,9 @@ allocator对象在进程与内核之间传递时一律使用内核空间的映
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*/
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void *memm_allocate(usize size, usize pid);
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#define memm_addr_set_allocator(mem, allocator) \
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*(allocator_t **)(mem - 16) = allocator;
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*(allocator_t **)((void *)(mem) - 16) = allocator;
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#define memm_addr_get_allocator(mem) \
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((*(allocator_t **)(mem - 16)))
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((*(allocator_t **)((void *)(mem) - 16)))
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void *memm_kernel_allocate(usize size);
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@ -200,6 +200,7 @@ void *memm_allocate(usize size, usize pid)
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ptr = new_allocator->allocate(&new_allocator->allocator_instance, orgsize, 0);
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after_allocation:
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if (ptr != nullptr)
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memm_addr_set_allocator(ptr, allocator);
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return ptr;
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}
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@ -1,6 +1,9 @@
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extern crate core;
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use core::alloc::{GlobalAlloc, Layout};
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use core::{
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alloc::{GlobalAlloc, Layout},
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ptr::null_mut,
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};
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extern "C" {
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pub fn memm_kernel_allocate(size: usize) -> *mut u8;
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@ -12,7 +15,14 @@ pub struct KernelAllocator {}
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unsafe impl GlobalAlloc for KernelAllocator {
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unsafe fn alloc(&self, layout: Layout) -> *mut u8 {
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memm_kernel_allocate(layout.size())
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let res = memm_kernel_allocate(layout.size());
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if res == null_mut() {
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panic!(
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"Kernel allocator failed to allocate {} byte(s) memory.",
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layout.size()
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);
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}
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res
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}
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unsafe fn dealloc(&self, ptr: *mut u8, _layout: Layout) {
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@ -96,6 +96,10 @@ SECTIONS {
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{
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*(.debug_pubtypes)
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}
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.debug_frame :
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{
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*(.debug_frame)
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}
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.kend :
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{
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*(.kend)
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